Day By Day
Notes for MATH 206
Fall 2009
Activity: Go over syllabus. Take roll. Functions activities. We will work in groups, and compare solutions.
Goals: Review course objectives: collect data, summarize information, and make inferences.
I have divided this course into three ÒunitsÓ. Unit 1 (Days 1 through 8) is about basic functions. Unit 2 (Days 9 through 17) is about derivatives and their uses. Unit 3 (Days 18 through 28) is about integration and multi-variable functions.
I believe to be successful in this course, you must READ the text carefully, working many practice problems. Our activities in class will sometimes be unrelated to the homework you practice and/or turn in for the homework portion of your grade; instead they will be for understanding of the underlying principles. For example, on Day 9 you will draw sample graphs and derivatives, then try to reconstruct the original graph. This is something you would never do in practice, but which I think will demonstrate several lessons for us. In these notes, I will try to point out to you when weÕre doing something to gain understanding, and when weÕre doing something to gain skills.
Each semester, I am disappointed with the small number of students who come to me for help outside of class. I suspect some of you are embarrassed to seek help, or you may feel I will think less of you for not Ògetting itÓ on your own. Personally, I think that if you are struggling and cannot make sense of what we are doing, and donÕt seek help, you are cheating yourself out of your own education. I am here to help you learn mathematics. Please ask questions when you have them; there is no such thing as a stupid question. Often other students have the same questions but are also too shy to ask them in class. If you are still too shy to ask questions in class, come to my office hours or make an appointment.
I believe you get out of something what you put into it. Very rarely will someone fail a class by attending every day, doing all the assignments, and working many practice problems; typically people fail by not applying themselves enough - either through missing classes, or by not allocating enough time for the material. Obviously I cannot tell you how much time to spend each week on this class; you must all find the right balance for you and your lifeÕs priorities. One last piece of advice: donÕt procrastinate. I believe mathematics is learned best by daily exposure. Cramming for exams may get you a passing grade, but you are only cheating yourself out of understanding and learning.
Today we will begin by discussing functions. Quite simply, a function is a rule. From an input value, a function gives the output value. The set of possible inputs is called the domain, and the set of output values is called the range. The input value is sometimes called the independent value, and the output value the dependent value. One of the chief goals of mathematics is to model real world phenomena with functions. Therefore it is important for us to be familiar with their uses and roles.
Throughout the course, we will try to look at functions from four different viewpoints. Data will be presented to us in tabular form, graphical form, algebraic form, or verbally. It will be up to us to determine the most appropriate method of describing the function. A common misconception that I hope to dispel is that equations are synonymous with functions. Equations are only one method of describing functions. Our text makes an honest effort to display functions for us in all four forms.
Today I would like to explore functions graphically, verbally, and algebraically. We will begin with a discussion of a hypothetical flight between two cities. Then I will have you work in groups on three projects.
In these notes, I will put the daily task in gray background.
I have three activities for us to become more familiar with functions.
Activity 1:
Graphical and Verbal Description.
The value of a car goes down as the car gets older, so we can think of the value of a car, V, in thousands of dollars, as a function of the age of a car, a, in years. We have V = f(a).
1) Draw a possible graph of V against a. You donÕt need scales on the axes, but label each axis as V or a.
2) What does the statement f(5) = 6 tell you about the value of the car? Be sure to use units for 5 and for 6. Label this as a point on your graph, and mark the 5 and the 6 on the appropriate axes.
3) Put a vertical intercept of 15 on your graph of the function. Explain the meaning of this vertical intercept in terms of the value of the car.
4) Put a horizontal intercept of 10 on your graph of the function. Explain the meaning of this horizontal intercept in terms of the value of the car.
Activity 2:
Algebraic and Verbal Description.
From a 24-inch length of string, form two geometric shapes, a circle and a square. Your goal is to create the smallest total area enclosed by both shapes (add the area enclosed by the square to the area enclosed by the circle, and make that total area small. Note: you will need to know the formulas for areas of circles and squares.) To begin this activity, I suggest trying some specific values. For example, what if the string is not cut at all? How much area will just a circle contain (the square has zero area)? How much area will just a square contain (the circle has zero area)? What if the string is cut in half instead? Then how much will the square contain, and how much will the circle contain? Then try a different breakdown, like ¼ of the string for the square and ¾ for the circle. My belief is that if you can figure out the areas for specific numbers, you can figure it out for arbitrary values, like x and 24 – x.
Activity 3:
Graphical and Algebraic Description.
With our calculators, we have the tools available to explore limits. Specifically, we can hone our intuition about this important topic in calculus.
1) Calculate for n = 1, 10, 100, 1000, etc. What seems to be happening to the terms? Can you explain it intuitively?
2) Calculate for n = 1, 10, 100, 1000, etc. What seems to be happening to the terms? Can you explain it intuitively? This limit we see here is a very important limit in calculus and mathematics. We will encounter it and study it in more detail later.
3) Consider this series: 1, 1/2, 1/3, 1/4, etc. Add successive terms to get a new series of partial sums. That is, find 1, 1+1/2, 1+1/2+1/3, 1+1/2+1/3+1/4, etc. What seems to be happening to these sums? Can you explain it intuitively?
4) Now try this series and repeat what you did in problem 3). 1/2, 1/4, 1/8, 1/16, 1/32, etc. That is, find 1/2, 1/2+1/3, 1/2+1/3+1/4, etc. (These are successively smaller powers of two.) What seems to be happening to these sums? Can you explain it intuitively?
5) Using , find the limits as you approach x = 2 from the right and left. (Approaching from the right means using values just above 2 and approaching from the left means using values just below 2.) Also find the value right at x = 2.
6) Repeat 5) using .
In these notes, I will put sections of computer commands in boxes, like this one. IÕm actually hoping that you already are quite familiar with this machine, having already taken MBA I. In these notes, I refer to the calculator as the TI-83. The same commands apply to the TI-84.
Y = is found on the top row of buttons, on the left. You enter equations into whichever Y-variable you want to use. Be careful to enter what you want, that is, pay attention to parentheses, typos, etc! Each Y-variable whose = sign is highlighted will be graphed when the GRAPH button is pressed. In addition, if any plots at the top of the display are highlighted, those too will be plotted, whether you intended them to be or not!
GRAPH is found on the top row of buttons, on the right. This button toggles between the data / numerical entry screens and the graphing window. To leave the graphing window, press any key, or press QUIT, (found by pressing 2nd MODE).
WINDOW is found on the top row of buttons, second from the left. This opens the windows setting screen, which tells you the dimensions and characteristics of the current graphing window. We will mostly change only 4 items: Xmin, Xmax, Ymin, and Ymax. If you like, you may tinker with the other settings.
TRACE is on the top row of buttons, second from the right. This key puts a cursor on the graphing window on one of your y-variables / functions. You may push right and left arrow to move sideways on the selected curve, or up and down arrow to select other curves (if you have entered more than one y-variable.) Be careful: TRACE is dependent on the current window settings. If you need precise values, after pressing TRACE, type the x-value you need evaluated. TRACE will calculate the functional value exactly.
ZoomFit (Zoom 0) Many times, you do not know which is the best viewing window. If you first specify the horizontal endpoints in the WINDOW settings screen (Xmax and Xmin), then you can press ZoomFit (under ZOOM menu, item 0) to have the calculator find the appropriate Ymin and Ymax values. This function is quite handy; I use it a lot myself.
ZStandard (Zoom 6) If you are in love with the numbers between –10 and +10, you should use ZStandard in the ZOOM menu. Otherwise, you may find this key useless!
Goals: (In
these notes, I will summarize each day's activity with a statement of goals for
the day.)
Introduce the course, and the idea of a function. Appreciate the dynamics of collaboration. Understand the different problem solving strategies. Explore some basic limits.
Skills: (In
these notes, each day I will identify skills I believe you should have after working the day's
activity, reading the appropriate sections of the text, and practicing
exercises in the text.
¥
Use the ÒGuess and CheckÓ method of problem solving. This
technique is the essence of the scientific method. There is nothing bad about guessing in order to learn. The better guessers, of course, tend to
get quicker results, but if you have appropriate tools to evaluate your
guesses, then even poor guesses can be refined adequately. By the way, your calculator in this
class will essentially use this guess and check method to solve equations. ItÕs just that your calculator works a
bit faster than you can. Another
related idea is using test numbers to start a process. That is, perhaps making up a sample
situation will help you see what is going on. I encourage you to use this approach often; it is the most
basic lesson my advisor taught me in graduate school. He used to say, ÒStart with a simple example.Ó That often meant assuming some specific
values for some variables, and working from there to understand the problem.
¥
Physical modeling.
Many times being stuck on a real
world problem can be alleviated by modeling the situation with physical items
or by other simulations. Of course
many situations are infeasible; you canÕt fly airplanes to simulate scheduling
airline routes, but you can use appropriate diagrams or tokens representing
airplanes. Sometimes actually
physically representing something will get you over that mental block.
¥
Collaboration.
One of the biggest problems I see
semester after semester with math students is their reluctance to talk about
their math frustration. Talk about things with each other! If you are too timid to talk to me, (or
if you have other reasons for not wanting to chat with me) at least talk to
your peers. Sometimes simply
saying something out loud will open up doors you might not have otherwise
opened, or an offhand remark may inspire someone elseÕs imagination. Of course this doesnÕt mean that one
person in a group of problem solvers should do all the work; but even if only
one group member ÔgetsÕ a solution, the sharing is beneficial to all
concerned. The sharer gets to really learn the concept as he/she is required to explain it; the others get to see a solution they
missed. Ideally, everyone should
be able to explain a group solution; until you can explain the solution, you
havenÕt quite understood the method.
¥
Evaluate limits numerically and graphically. By
using numbers closer and closer to the value in question, whether it is finite
or infinite, your calculator or computer can help you to evaluate limits. There is a caution, however: you must
still use your analytic skills to avoid being fooled. You may have observed this in Exercise 2 of Activity 3. Some limits are easy to evaluate
(simply plug in and evaluate) while others are more complicated (the partial
sums we saw in Exercises 3 and 4 of Activity 3 are often quite difficult to
evaluate or to even decide if they converge.) One of the Òbig ideasÓ in calculus is differentiation, and
we need to be comfortable with limits to understand derivatives. Another of the Òbig ideasÓ in calculus
is integration, and we need to understand limits such as partial sums to
understand integrals.
¥
Recognize the harmonic series. Even though terms in a
series may be getting smaller and smaller, their partial sums may not converge
to a finite number. The sequence
in Exercise 3 of Activity 3 above is called the harmonic series and demonstrates this seeming paradox. Many partial sums will converge,
though, as you saw in Exercise 4 of Activity 3, which is an example of a geometric
series.
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Understand the definition of the number e .
Exercise 2 of Activity
3 is the definition of the number e,
which we will use again and again in calculus. Remember, though, e is just a number, nothing more.
DonÕt be afraid of it!
Reading: Sections 1.1 to 1.3. Bring your calculator to class every day. It will be an invaluable tool.
Activity: Using the Olympic data, fit a regression line to predict the 2008 and 2012 race results. Interpreting Rates of Change.
Unit 1 is about building up a library of functions. To be an effective mathematical modeler, we must have a working knowledge of basic functions. These include linear functions, exponential functions, polynomials, and combinations of these. The simplest and most used (it is the basis for the derivative we will master in Chapter 2) is the linear function. You should already know a lot about linear functions. Just to make sure we all have the same background, today we will explore linear functions in detail.
To begin, I will list the useful forms for linear equations.
1) Slope/Intercept form: . In this form, m is the slope and b is the y-intercept.
2) Point/Slope form: . In this form, m is the slope, and (x1, y1) is an ordered pair on the line.
3) Two Point form: . In this form, (x1, y1) and (x2, y2) are two sets of ordered pairs on the line.
I will use do the Celsius/Fahrenheit
conversion in class to demonstrate using these forms.
The chief technique for summarizing a linear relationship given data points on a scatter plot is Least Squares Linear Regression. This technique is also known as Least Squares Regression, Best Fit Regression, Linear Regression, etc. The important point is that we are going to describe the relationship with a straight line, so if the scatter plot shows some other shape, this technique will be inappropriate. Your tasks are to 1) come up with a line, either by hand or with technology, that Ògoes throughÓ the data in some appropriate way, 2) to be able to use this model to describe the relationship verbally, and 3) to predict numerically y-values for particular x-values of interest.
While we wonÕt cover regression in complete detail, the text does go over it on pages 80 to 82, so it might be worthwhile for you to look at those sections of the text in addition to the regular reading.
Activity 1:
Graphical description: Using linear regression.
Begin by making a scatter plot of the race times. (Use STAT PLOT. See calculator commands below.) If you want a rough guess for the slope of the best fitting line through the data, you can connect two points spaced far apart (I will show you the details in class.)
Next, use the TI-83Õs regression features to calculate the best fit. The command is STAT CALC LinReg(ax+b), assuming the two lists are in L1 and L2. (L1 will be the horizontal variable, years in this case.) (For regression it is vital that you get the order of the variables correct; the idea here is that you are predicting the vertical variable from the known horizontal variable.)
Interpret what your two regression coefficients mean. Make sure you have units attached to your numbers to help with the meanings.
Have the calculator type this equation into your Y = menu (using VARS Statistics EQ RegEQ or use the commands below), and TRACE on the line to predict the future results. Specifically, see what your model says the 2008 and 2012 times should have been. Then we will look them up and check how predictive our model is.
Activity 2:
Algebraic description: Using verbal description.
Taxicab rates. Given the following information on the side of a cab, develop an equation that will let you calculate the fare for any distance x. So, if someone tells you the distance they want to travel, your formula will tell them the fare.
Info on the side of a
cab: $2.50 FOR THE FIRST 1/9 MILE, PLUS 25
CENTS FOR EACH ADDITIONAL 1/9 MILE OR FRACTION OF A MILE.
Activity 3: Tabular
description: Using average rates of change.
A half-marathon runner records the following times during a race. Find the average speed of the runner from the start through mile 6. From the end of six miles through the end of the race. For the whole race. For just the last 3.1 miles. Report your answers on the board.
Mile |
Time on Clock |
Mile |
Time on Clock |
1 |
7:36 |
7 |
55:07 |
2 |
15:29 |
8 |
1:02:50 |
3 |
23:25 |
9 |
1:10:29 |
4 |
31:23 |
10 |
1:18:20 |
5 |
39:20 |
11 |
1:26:08 |
6 |
47:18 |
13.1 |
1:42:58 |
MenÕs and WomenÕs
100-meter dash winning Olympic times:
1896 |
Thomas
Burke, United States |
12
sec |
|
|
1900 |
Francis
W. Jarvis, United States |
11.0
sec |
|
|
1904 |
Archie
Hahn, United States |
11.0
sec |
|
|
1908 |
Reginald
Walker, South Africa |
10.8
sec |
|
|
1912 |
Ralph
Craig, United States |
10.8
sec |
|
|
1920 |
Charles
Paddock, United States |
10.8
sec |
|
|
1924 |
Harold
Abrahams, Great Britain |
10.6
sec |
|
|
1928 |
Percy
Williams, Canada |
10.8
sec |
Elizabeth
Robinson, United States |
12.2
sec |
1932 |
Eddie
Tolan, United States |
10.3
sec |
Stella
Walsh, Poland (a) |
11.9
sec |
1936 |
Jesse
Owens, United States |
10.3
sec |
Helen
Stephens, United States |
11.5
sec |
1948 |
Harrison
Dillard, United States |
10.3
sec |
Francina
Blankers-Koen, Netherlands |
11.9
sec |
1952 |
Lindy
Remigino, United States |
10.4
sec |
Marjorie,
Jackson, Australia |
11.5
sec |
1956 |
Bobby
Morrow, United States |
10.5
sec |
Betty
Cuthbert, Australia |
11.5
sec |
1960 |
Armin
Hary, Germany |
10.2
sec |
Wilma
Rudolph, United States |
11.0
sec |
1964 |
Bob
Hayes, United States |
10.0
sec |
Wyomia
Tyus, United States |
11.4
sec |
1968 |
Jim
Hines, United States |
9.95
sec |
Wyomia
Tyus, United States |
11.0
sec |
1972 |
Valery
Borzov, USSR |
10.14
sec |
Renate
Stecher, E. Germany |
11.07
sec |
1976 |
Hasely
Crawford, Trinidad |
10.06
sec |
Annegret
Richter, W. Germany |
11.08
sec |
1980 |
Allen
Wells, Britain |
10.25
sec |
Lyudmila
Kondratyeva, USSR |
11.6
sec |
1984 |
Carl
Lewis, United States |
9.99
sec |
Evelyn
Ashford, United States |
10.97
sec |
1988 |
Carl
Lewis, United States |
9.92
sec |
Florence
Griffith-Joyner, United States |
10.54
sec |
1992 |
Linford
Christie, Great Britain |
9.96
sec |
Gail
Devers, United States |
10.82
sec |
1996 |
Donovan
Bailey, Canada |
9.84
sec |
Gail
Devers, United States |
10.94
sec |
2000 |
Maurice
Greene, United States |
9.87
sec |
Marion
Jones, United States |
10.75
sec |
2004 |
Justin
Gatlin, United States |
9.85
sec |
Yuliya
Nesterenko, Belarus |
10.93
sec |
2008 |
Usain
Bolt, Jamaica |
9.69
sec |
Shelly-ann
Fraser, Jamaica |
10l78
sec |
2012 |
? |
|
? |
|
(a) A 1980 autopsy determined that Walsh
was a man.
MenÕs and WomenÕs 200-meter dash winning Olympic times:
1900 |
John
Tewksbury, United States |
22.2
sec |
|
|
1904 |
Archie
Hahn, United States |
21.6
sec |
|
|
1908 |
Robert
Kerr, Canada |
22.6
sec |
|
|
1912 |
Ralph
Craig, United States |
21.7
sec |
|
|
1920 |
Allan
Woodring, United States |
22
sec |
|
|
1924 |
Jackson
Scholz, United States |
21.6
sec |
|
|
1928 |
Percy
Williams, Canada |
21.8
sec |
|
|
1932 |
Eddie
Tolan, United States |
21.2
sec |
|
|
1936 |
Jesse
Owens, United States |
20.7
sec |
|
|
1948 |
Mel
Patton, United States |
21.1
sec |
Fanny
Blankers-Koen, Netherlands |
24.4
sec |
1952 |
Andrew
Stanfield, United States |
20.7
sec |
Marjorie,
Jackson, Australia |
23.7
sec |
1956 |
Bobby
Morrow, United States |
20.6
sec |
Betty
Cuthbert, Australia |
23.4
sec |
1960 |
Livio
Berruti, Italy |
20.5
sec |
Wilma
Rudolph, United States |
24.0
sec |
1964 |
Henry
Carr, United States |
20.3
sec |
Edith
McGuire, United States |
23.0
sec |
1968 |
Tommy
Smith, United States |
19.83
sec |
Irena
Szewinska, Poland |
22.5
sec |
1972 |
Valeri
Borzov, USSR |
20.00
sec |
Renate
Stecher, E. Germany |
22.40
sec |
1976 |
Don
Quarrie, Jamaica |
20.23
sec |
Barbel
Eckert, E. Germany |
22.37
sec |
1980 |
Pietro
Mennea, Italy |
20.19
sec |
Barbara
Wockel, E. Germany |
22.03
sec |
1984 |
Carl
Lewis, United States |
19.80
sec |
Valerie
Brisco-Hooks, United States |
21.81
sec |
1988 |
Joe
DeLoach, United States |
19.75
sec |
Florence
Griffith-Joyner, United States |
21.34
sec |
1992 |
Mike
Marsh, United States |
20.01
sec |
Gwen
Torrance, United States |
21.81
sec |
1996 |
Michael
Johnson, United States |
19.32
sec |
Marie-Jose
Perec, France |
22.12
sec |
2000 |
Konstantinos
Kenteris, Greece |
20.09
sec |
Marion
Jones, United States |
21.84
sec |
2004 |
Shawn
Crawford, United States |
19.79
sec |
Veronica
Campbell, Jamaica |
22.05
sec |
2008 |
Usain
Bolt, Jamaica |
19.30
sec |
Veronica
Campbell-Brown, Jamaica |
21.74
sec |
2012 |
? |
|
? |
|
STAT EDIT To enter a list of numbers into your calculator, instead of an equation, use the STAT menu. EDIT is the display that allows you to enter lists of numbers. You may have up to 3 lists displayed in the EDIT window. It is convenient to use the built-in lists L1 to L6, but actually any named lists may be used. You may want to refer to the calculator manual if you are interested in naming and saving your lists. (It might save you having to constantly re-enter data.)
STAT PLOT 1 On Use this screen to designate the plot settings. You can have up to three plots on the screen at once.
ZOOMStat (Zoom 9) To view a scatter plot of two lists, ZoomStat will create an appropriate viewing window. To use the TI-83 to effectively view scatter plots, I recommend turning off or de-selecting all Y-variables before pressing ZoomStat. There will be times however, when you will want to have both a scatter plot and an equation on the same viewing window, so it is not required to always de-select all functions.
STAT CALC ???Reg After two lists of numbers have been entered, we can fit lines or curves to the data with the ???Reg commands. The TI-83 will fit 10 kinds of equations; the most common one is LinReg. Before you use any of the fitting routines, perform the following: Press CATALOG (found by pressing 2nd 0), the letter D, down arrow eight times (to point to DiagnosticOn), and press ENTER twice.
If you want to store your fitted equation in the Y= list directly from the regression command, do this: press STAT CALC ???Reg, then indicate the lists (variables) you want to use, separated by commas, then press VARS, right arrow, 1, and choose the desired Y-variable. Your fitted equation then appears in your list of Y-variables. An example command is: LinReg(ax+b) L1, L2, Y1. This will use L1 as the x-values, L2 as the y-values, and Y1 as the equation to store the fitted equation in. Be aware though that this command will overwrite anything you already had stored in Y1. Make sure important stuff in Y1 is saved elsewhere before you perform this command.
Goals: Practice
using regression with the TI-83.
We want the regression equation, the regression line superimposed on the
plot, and we want to be able to use the line to predict new values. Understand the slope of the line is
important to the Rate of Change.
Skills:
¥
Fit a line to data.
This may be as simple as
ÔeyeballingÕ a straight line to a scatter plot. However, to be more precise, we will use least squares, STAT CALC LinReg(ax+b)
on the TI-83, to calculate the coefficients, and VARS Statistics EQ RegEQ to type the
equation in the Y=
menu. You should also be able to
sketch a line onto a scatter plot (by hand) by knowing the regression
coefficients.
¥
Interpret regression coefficients. Usually,
we want to only interpret slope, and slope is best understood by examining the
units involved, such as inches per year or miles per gallon, etc. Because slope can be thought of as
ÒriseÓ over ÒrunÓ, we are looking for the ratio of the units involved in our
two variables. More precisely, the
slope tells us the change in the response variable for a unit change in the
explanatory variable. We donÕt
typically bother interpreting the intercept, as zero is often outside of the
range of experimentation.
¥
Estimate/predict new observations using the regression
line. Once we have calculated a regression equation, we can use it to predict
new responses. The easiest way to
use the TI-83 for this is to TRACE on the regression line. You may need to use up and down arrows
to toggle back and forth from the plot to the line. You may also just use the equation itself by multiplying the
new x-value by the slope and adding the
intercept. (This is exactly what TRACE is
doing.) Note: when using TRACE, and the x-value you want is currently outside the window
settings (lower than Xmin or above Xmax) you must reset the window to include your x-value first.
¥
Convert a verbal description into an equation. You
should be able to recognize the ideas of slope / intercept or a description of
several points on a line from a verbal description of a linear function. By recognizing which information is
present, you then should be able to choose the proper form for the linear
equation.
¥
Be able to calculate average rates of change from tabular
data. Given a table of values, you should be able to calculate various rates
of change. The important concept
is that the average rate of change is simply the slope from a linear equation.
Reading: Section 1.4.
Activity: Economics Examples. Quiz 1 today.
Several important business/economic applications use linear functions. Today we will look at profit, marginal costs, depreciation, and supply/demand curves. All of these topics can be modeled with non-linear functions, so we will encounter them later. For now, however, we will use only the linear functions.
Profit: In business settings, profit is calculated by subtracting costs from revenue.
Marginal Costs: The concept of marginal costs, revenues, etc. is a notion about the next itemÕs cost, revenue, etc. Recognizing the difference between a marginal cost and an average cost is critical to using derivatives appropriately later (Chapter 2).
Depreciation: Items lose value over time, and we model this with different functions. With linear depreciation, we basically use a two-point form.
Supply/Demand Curves: Economists theorize that markets can be modeled with supply and demand curves, where the supply curve applies to producers of a commodity and the demand curve applies to the consumers. One interesting modification we can make to the supply and demand setting is adding various kinds of taxes. The basic question is how taxation affects market equilibrium. For the problems today, we will consider various points of view. For example, when we charge the producer the tax on an item, as opposed to charging the consumer, the producer behaves as if the product sells for less than the cost the consumer pays. Therefore we replace p with p – t, where t is the amount taxed per item. With the new equation, we now have a new equilibrium, and new total profits, which we can now compare to the values before the tax.
Today we will look at examples of each of the above topics. For each exercise, put your groupÕs solution on the board. After the quiz, I will stay to answer any questions you might have, or to help you work through any problems you're having.
Revenue, Cost, Profit using linear functions. Marginal Cost/Revenue. Problem 9, page 30.
Linear Depreciation. Problem 16, page 30.
Supply/Demand using curves. Problem 20, page 31.
Modeling. Problems 27 and 28, page 32.
Supply/Demand using lines. Effect of taxes. Problems 35 to 37, page 32.
Goals: Recognize
the application of linear functions to economic examples.
Skills:
¥
Understand profit functions. Profit is defined as
the difference between Revenue and Cost.
We often phrase these functions in terms of quantity produced, q. Revenue as a function of quantity is
usually linear. Cost as a function
of quantity is usually not linear, but
today we will assume it is to make some calculations. Marginal cost (revenue, profit) is the cost (revenue,
profit) of the next item
produced. Marginal values are
often different, based on current production levels. We will explore marginal values more in Chapter 2 on
derivatives.
¥
Understand linear depreciation. In general,
depreciation is the declining value of an item over time. The simplest form of depreciation is
linear depreciation. The usual
method of determining a linear equation for linear depreciation is to use the
two-point form.
¥
Understand supply and demand curves. Economic
theory suggests that prices and quantities produced or desired are related. The demand curve suggests that as price increases, fewer
people will buy an item. The supply curve suggests that as price increases, more items
will be produced. These two curves
can be modeled with linear functions, and economic theory says they intersect
at equilibrium. Later, we will explore non-linear
supply and demand curves (Section 6.2, Day 21).
Reading: Sections 1.5 and 1.6.
Activity: Exponential and Logarithmic Functions. Homework 1 due today.
In linear functions, as the x-value increases one unit, the y-value increases m units, where m is the slope of the line.
This is additive growth. Another type of growth is multiplicative. In
this kind of growth, when the x-value increases one unit, the y-value increases by a factor of b. That is,
instead of adding a fixed value, we multiply by a fixed value. This kind of growth is called exponential growth.
Famous examples of exponential growth are
populations. I will look at the US
population. In Presentation 1, you
will select an individual state and model its growth, perhaps efficiently with
exponential curves. (Some
populations do not grow exponentially;
you will have to explore the growth rates to see.)
To use an exponential growth function, we start with a known x-value, such as a time. The exponential formula then gives us the height of the function, or the y-value. In many situations, however, we want to work in the other direction. That is, we know the height of the function (the y-value), but want the time when that happens (or the x-value). This inverse is called a logarithmic function. I have found that many students are rather confused by logarithms. I will try to alleviate this confusion by emphasizing the fact that exponentials and logarithms belong together, much like squares and square roots do, or multiplication and division do. There are rules we must learn to do algebra with exponential functions however; for example when we solve for time in an exponential growth model.
Today we will use the
calculator to fit exponential curves to growth functions, like the US
population over time. We will also
explore e, and the log rules.
Activity 1: Modeling
Population Growth.
The population for the US is on page 213. (I also have the numbers at the end of these notes.) Using ratios, find periods of time when the US population grew approximately exponentially. For your candidate eras, fit an exponential model using regression.
Activity 2:
Discovering e.
As we saw on Day 2, the number e is a limit of the calculation as n gets large. However, you need to be careful not to let your calculator fool you. For example, try values of n from 1010 to 1014. With such large values for n, your calculatorÕs precision capabilities are exceeded. In your groups, try to come up with an explanation of what the calculator is having trouble with.
Activity 3: Rules.
Using test values,
explore the rules for exponents and logs.
Explore , , and . Now look at , , and . I will ÒproveÓ
each of the results using algebra.
Practice the rules using 1-16 on page 43.
STAT CALC ExpReg This regression functions fits
exponential curves. Again, the x-variable comes first, then the y-variable.
The third parameter, if used, is the Y-variable where the equation will be
stored. Example: ExpReg(ax+b) L1, L2, Y1 uses data
from lists L1 and
L2 and stores
the equation in Y1.
Goals: Explore
exponential growth, and its inverse, the logarithm.
Skills:
¥
Know the form of the exponential functions. Exponential
equations have two parameters, a y-intercept, and a base. The base is the multiplicative growth
factor. The general equation is . You should be
familiar with the shape of the exponential graphs, as well as the domain and
range.
¥
Know the multiplicative nature of exponential
functions. In contrast to linear functions growing at a steady
rate over time, exponential functions grow at an increasing rate. The ratio of successive y-values for equally
spaced x-values is a constant. This fact is especially useful for
checking whether tabled values grow exponentially, but only if
the table has equally spaced values of the independent variable.
¥
Understand the relationship between exponential and
logarithmic functions. Logarithmic functions are inverses to exponential
functions. This means that we
reverse the x and y values
and their associated facts. For
example, the range of the exponential functions is only positive
numbers; therefore the domain of the
logarithmic functions is also only positive numbers.
¥
Understand the definition of the number e (approximately 2.7182818). Exercise 2 of Activity 3 from Day 1 is
the definition of the number e, which we
will use again and again in calculus.
Remember, though, e is
just a number, nothing more. The
importance of e will become more
clear when we explore derivative formulas in Chapter 3.
¥
Know the exponential and logarithmic properties and be able
to use them to solve equations. To solve equations for variables that appear in
exponents, we need logarithmic functions.
Therefore, you must know the properties. In particular, you must be comfortable using and . The second property
is how we ÒrescueÓ a variable from the exponent.
Reading: Sections 1.7 and 1.8.
Activity: Growth and Decay. Transformations. Quiz 2 today.
Doubling time in an exponential function is the length of time it takes the y-value to double. To find it algebraically, suppose that a function has doubled between times x1 and x2. So, (because it is an exponential function) and y2 = 2 y1 because it has doubled. Putting these two expressions together gives . If we now solve for the change in time, x2 – x1, we will have found the doubling time.
Examples of exponential functions that are quite useful in business are the Present Value and Future Value formulas on page 49. You may have had some experience with these functions in the finance section of MATH 204. We will explore them briefly as examples of exponential growth or decay.
There are several hallmarks of growth functions, and you should be able to tell growth from decay just by looking at the formula. If the base of an exponential function is greater than 1, we have a growth function, and vice versa. The tricky part of checking this feature out is the case where we have negative exponents. For example, . So at first we might think this is growth function because 2 > 1, but after the algebra we see the negative exponent shows this is a decay function, because .5 < 1.
Our other topic today is transformations, creating new functions from old. In particular, we will explore shifts, stretches/compressions, and compositions. When a constant is added to the y-value, we have a vertical shift. When a constant is added to the x-value, in parentheses, we have a horizontal shift. When the y-value is multiplied by a constant, we have a vertical stretch/compression. When the x-value is multiplied by a constant, we have a horizontal stretch/compression.
Composed functions are very important to
understand for being able to use the chain rule later. Basically, when we have a function
inside parentheses, we have a composed function. The important skill with these composed functions is
identifying the ÒinnerÓ and ÒouterÓ functions. See class notes for examples.
Today we will practice
using exponential and logarithmic functions. Then we will explore creating new functions from linear and
exponential functions. In
particular we will explore composed
functions, which are critical to understanding the chain rule of Chapter 3.
Activity 1: Doubling
Times. Tripling Times. Etc.
Using a graph, explore the relationship between doubling time and the base b. Choose a value for b; by guessing and checking, determine an interval where the y-value has doubled. Calculate the doubling time by subtracting the two x-values. Repeat this calculation with a different interval where the y-value has doubled. You should notice an interesting fact.
Repeat now for tripling time. Also, try a different value for the base. Make a conjecture about the effects of the base and the multiplier (doubling, tripling, etc) on the times. Can you support your conclusions using algebra?
Activity 2:
Comparing compound interest rates.
A stock has current value $150 per share and is expected to increase in value by 8% each year. In each case below, find a formula for the value of the stock t years from now and calculate the value of the stock in 10 years:
Interpret the 8% return as an annual (not continuous) rate.
Interpret the 8% return
as a continuous annual rate.
Now graph both functions on the same axes. What is the effect of continuous versus annual compounding? Write a short summary.
Activity 3: Using
Present Value and Future Value formulas.
Work on problem 31 page 51. Hints: Treat each year as a separate investment. For example, the bonus is put into one account at the bank. Then after each year, that yearÕs salary is put into a separate account, etc. What is different about these accounts is the length of time they exist. Then add all the account balances together to get the total amount.
Activity 4: Using
the ÒRule of FourÓ with various composed functions.
We will use all four approaches (verbal, graphical, algebraic, and tabular) to become familiar with composed functions and transformations. Verbal: problem 35 page 56. Graphical: problems 32-34 page 56. Algebraic: problem 42 page 73. Tabular: problem 31 page 56.
Goals: Become
familiar with manipulating exponential functions. Become familiar with transformations, especially composed
functions.
Skills:
¥
Know facts about Doubling Times. The most important fact
about doubling time is that for any exponential function, it is the same
value. That is, if an exponential
function doubles from time t = 3 to t = 13, it will also double between t = 20 to t
= 30. From our algebraic work on
Activity 1, the doubling time is .
¥
Be able to use Present Value and Future Value formulas in
practical settings. The Present Value and Future Value formulas are
examples of exponential functions.
You should know facts about these formulas. For example, is an
exponential function in the variable t. The base is (1 + r),
which is greater than one, so it is a growth function. P is the y-intercept.
¥ Recognize the basic functions in complicated functions, especially the shifts and stretches. Adding and multiplying by constants create shifts and stretches. You should be able to identify the basic function being manipulated, and also the shifts and stretches taking place.
¥ Be able to decompose functions into the sequential steps. To use the chain rule to take derivatives, in Chapter 3, we need to be able to recognize the components in composed functions. The ÒinnerÓ function usually is inside parentheses, and the ÒouterÓ function is the function that results if you replace the expression inside the parentheses with x.
Reading: Section 1.9.
Activity: Power functions and polynomials. Homework 2 due today.
Power functions have the form . Note the apparent similarity to exponentials. It is up to you to remember which is which. My personal reminder is that x2 is a polynomial. You should be able to deal with fractional and negative exponents. Fractional exponents are radicals like square root (an exponent of 0.5 or ½) while negative exponents are reciprocals ().
Polynomials are several power functions
(with positive integer exponents) added together. The degree of the
polynomial is the highest power of x. An nth
degree polynomial can have up to n
– 1 turning points. However,
there are often fewer, such as with x3, which has none, but is a 3rd degree
polynomial.
We should also understand the asymptotic
behavior of polynomials. As x gets large, only the term with the largest exponent
matters. To see this, start with a
polynomial that has turns and gradually increase the x-value until the graph looks like only the leading
term. (See Activity 1.) Pages 92 to 94 in the text elaborate on
this endpoint behavior.
We should have some extra time in class today for you to work on your presentations for next time.
Today we will play around with polynomials, a versatile class of functions. They can take on a variety of shapes, but we should understand their behavior before settling on them as final models to our data.
Activity 1:
Exploring polynomial turning points.
Using trial and error,
create a cubic that has 1) zero turning points 2) one turning point, and 3) two
turning points. Now try the same
thing for a quartic (4th degree polynomial), with up to three
turning points. In each case,
explore the endpoint behavior by comparing the cubic or quartic to x3 or x4 with large x-values.
After we study Chapter 3, we will be able to better qualify when a polynomial has 0, 1, 2, etc. turning points.
Activity 2:
Recognizing power functions versus exponentials.
Values of three functions are given below (the numbers have been rounded off to two decimal places). Two are power functions and one is an exponential. Classify them and find potential equations. You may find the regression functions especially helpful here. But you can also use algebra as a solution method.
x |
f(x) |
x |
g(x) |
x |
h(x) |
8.4 |
5.93 |
5 |
3.12 |
.6 |
3.24 |
9 |
7.29 |
5.5 |
3.74 |
1.0 |
9.01 |
9.6 |
8.85 |
6.0 |
4.49 |
1.4 |
17.66 |
10.2 |
10.61 |
6.5 |
5.39 |
1.8 |
29.19 |
10.8 |
12.60 |
7.0 |
6.47 |
2.2 |
43.61 |
11.4 |
14.82 |
7.5 |
7.76 |
2.6 |
60.91 |
Activity 3: Explore
the asymptotic dominance of exponentials to polynomials.
No matter the degree,
no matter the base of a growth model, an exponential function will be larger
than a power function for large enough values of x. First
look at problem 28 page 96. Then
change the base to 1.5 and the power to 10. Zoom out sufficiently to verify that , for large enough x. (If you are having
trouble finding a window that verifies this, look at the answer on the next
page, in the reading.)
Goals: Understand the features of polynomials
and power functions.
Skills:
¥
Know about power functions and their attributes. Power
functions have a number of features you should be aware of. Even powered functions are non-negative
and symmetric about x = 0.
Odd powered functions are symmetric about the origin. The higher the power, the quicker the
function goes to infinity.
Fractional powers are only defined for positive x-values.
Negative powers have a vertical asymptote at x = 0.
¥
Know the basic facts about polynomials. Polynomials
are sums of power functions with positive integer exponents. The degree is the largest power of x. An nth degree polynomial can have up to n – 1 turning points. Endpoint behavior is determined by the term with the largest
power.
¥
Know the asymptotic dominance of exponentials over
polynomials. Slowly growing exponentials may be dominated by
polynomials for small x-values. However, for large enough x-values, exponentials (growth models) will always exceed
polynomials. We call this
Òendpoint behaviorÓ and it is important in analyzing functions qualitatively.
Reading: Section 2.1. (Activity 3 window: x: 100 to 130 y: 0 to 2e21.)
Activity: Presentation 1. Instantaneous Change.
Pick one of the 50 states. (The data is at the end of these notes.) Fit a model to its population growth. You have two goals: describe the growth, and predict the 2010 census. Compare linear, exponential, and polynomial models. Your presentation should convince us that you have chosen the most appropriate descriptive model and that your estimate for 2010 is believable.
Today we begin Chapter 2, the derivative. The derivative at a point is the slope of a line that is ÒparallelÓ to the curve at that spot. We will use a variety of techniques to approximate this slope, depending on the sort of information available to us. With equations, we can use more and more precise Òtwo pointÓ estimates, or slopes of secant lines; after Chapter 3, we will use formulas instead. If we have tabled data, we will not have precise estimates, as we can only Òzoom inÓ as much as the table allows. If we have graphs, we will have to guess using a straightedge. In any case, weÕre seeking the slope of the line, and therefore the units are a ratio, like miles per gallon, or feet per second, depending on the units used for the two variables.
I have two activities today to explore instantaneous change, or derivative. Both relate to the fact that if we zoom in close enough on any continuously differentiable (or smoothly curving) function, the function will resemble a straight line. This phenomenon is called local linearity.
Activity 1:
Exploring Local Linearity. Using Tangent on the
TI-83.
Graph the function on the standard window. Zoom in on what you think is the curviest spot. Keep zooming in, say 8 times. Using two points on the ÒlineÓ, estimate the equation of the line this zoomed in function is close to. Graph your candidate in the same window.
Now, at your selected x-value, use the Tangent function to get an equation of the line. Compare to your estimate from the Òtwo pointÓ method above. Note the Tangent function reports the entire equation of the tangent line; often we are only interested in the slope.
Activity 2:
Estimating the derivative at a point using secant lines.
The derivative at a point can be approximated with an appropriately chosen secant line, that is a line between two well-chosen points on the curve. The following exercise should help you see what the calculator is doing when it calculates Tangent.
Fill in the table,
using x = 7, and f(x) =
sin(x). Compare your answers with the others in your group. You may be getting different
answers. If so, explain whose
values are ÒcorrectÓ. Note that
the two y-values forming the
numerator of the secant slope are either or .
h |
f(x - h) |
f(x + h) |
Secant slope |
.1 |
|
|
|
.01 |
|
|
|
.001 |
|
|
|
Now graph f(x) = sin(x), making sure that your window includes the point where x = 7. Use the DRAW-Tangent feature and draw a tangent line on your window. Now, use the dy/dx key on the CALC menu. How do these two techniques compare numerically? Graphically? Is one preferable over the other?
Compare the definition of the derivative (page 135) with your calculations when filling out the table. Observe how the calculator computes derivative values with dy/dx. However, sometimes we cannot use our calculators (perhaps a parameter in the equation has an unknown or variable value) and we must use our algebra skills. Specifically, notice how our authors do algebraic derivatives on page 137. DonÕt fear, though, you wonÕt be able to use this method for all problems, so we will need other tools (theorems) to help us, and when we actually calculate derivatives, we will use rules, not this definition.
Zoom In (ZOOM 2) allows us to make the window ÒcloserÓ by a factor of four. To use it, press ZOOM 2, then move the cursor to where you want the new window to be centered, then press ENTER.
The CALC menu (found by pressing 2nd TRACE) is most useful to calculus. The functions in this menu will allow us to find minimum and maximum values, find roots of equations, and perform the differentiation and integration activities of calculus. We will explore the syntax of these commands as we use them. Today we used dy/dx, which gives the slope of the tangent line at that point.
The DRAW menu (found by pressing 2nd PRGM) will allow you to draw various lines and shapes on your window. In particular, we will want to draw ÒtangentÓ lines to curves. These tangent lines are straight lines that just touch a curve at a point, and are in some sense ÒparallelÓ to the curve at that point. DRAW - Tangent can be used in two ways: from an existing graph, or from the calculation screen. To use it for an existing graph in the graphing window, make sure you have the point of interest on-screen. Then press DRAW - Tangent. Select the curve you want using up or down arrow, if you have more than one curve graphed. Choose the x-value you want by using right or left arrow or by typing the x-value of interest. Finally press ENTER. The command syntax from the calculation screen is: DRAW – Tangent(Y#, x), where Y# is the curve of interest (such as Y1, or Y2, etc.) and x is the point at which you want to have the tangent line drawn.
Goals: Understand
that most functions we look at are Òlocally linearÓ. Understand slopes of secant lines as approximations for the
slope of the tangent line.
Skills:
¥
Understand the definition of derivative as the slope of the
tangent line. The tangent line just touches a curve at the point
of interest, and is in a loose sense ÒparallelÓ to the line. The slope of this line is the derivative at that point. Because it is the slope of a straight
line, we know much about its features: it is a rate of change (rise over run),
it is important to know the sign, etc.
¥
Evaluate derivatives numerically. If your calculator can
produce numerical values for a function (whether from a formula or just from
some calculation), and the input values can be arbitrarily close together (that
is what h approaching zero means), then you can calculate a
derivative numerically. You must
calculate the slopes of some secant
lines, and should evaluate several such slopes, making sure the limit in fact
does exist. You must also realize
you may have the only estimated
the value of the derivative, and the exact value may only be close to the value you have. For more exact values, either use the algebraic approach, or
look ahead to the theorems we will encounter in Chapter 3.
¥
Evaluate derivatives graphically. If you can phrase a
function in the form of an equation, then your graphing calculator can help you
calculate a derivative at specific input values. The TI-83 can draw tangent lines at various places on a
curve, and can calculate derivatives numerically as well, displayed on the
graphing window.
¥
Understand the definition of the derivative. You
should be comfortable with the notion of a limit of slopes of secant line. You should also be comfortable with the
equations and . (Note that the second equation is
precisely the limit of slopes of secant line. See page 135.)
This last expression differs slightly from Activity 2 today; I
personally think it makes more sense to center the secant line on the x-value
instead of favoring the right side.
It should make no difference in the limit, but practically we can only
make h so small using our TI-83.
¥
Know several methods of estimating the derivative at a
point. If we have a formula, we can use successively narrower intervals and
use the Òtwo pointÓ form for a line to estimate a slope at a point. After Chapter 3, we may be able to use
a formula approach. If we have
tabular data, we can only estimate roughly the slope of the tangent line, using
secant lines. If we have a graph,
we can estimate slopes using a straightedge.
Reading: Chapter 1.
Activity: Exam 1.
This first exam will cover the elementary functions of Chapter 1. Some of the questions may be multiple choice or T/F. Others may require you to show your worked out solution.
Reading: Sections 2.2 and 2.3.
Activity: Sketching the derivative function. Interpreting the derivative function.
The derivative is a slope of a function at a particular point. If we evaluate the derivative at many such x-values, and graph the result, we have the derivative function. This is a graph, just like the original function, but with different interpretations, as the y-values are now the slopes at each x-value, instead of the original functional values. Today we will begin by estimating the derivative function from tabular data. Then we will estimate functional values by knowing the derivative at a point.
Our second and third activities today
involve a graphical exercise. After
the activities, we will look at a handy function on the calculator that will
approximate the derivative at all x-values
in the graphing window. See
calculator commands below.
Comment on notations: There are two main
notations mathematicians have used to designate derivatives. I will use them interchangeably,
without thinking, as it is second nature to me. These notations are:
1)
Prime notation. .
2)
Leibniz notation.
This notation reminds us that derivative is a ratio of differences, a
slope. Either we use Dy/Dx or dy/dx. One
advantage of Leibniz notation is that we get to see the actual variables
involved. Many times with the Òf-primeÓ notation we just say Òf-primeÓ.
This isnÕt very illuminative.
What are the variables!
Unfortunately, though, Leibniz notation doesnÕt allow us to specify which
x-value weÕre talking about. In fact, to designate which x-value weÕre using becomes quite cumbersome. Page 113 shows you the messiness.
Activity 1:
Estimating the derivative using tabular data.
Using the following half-marathon times, find the estimated derivative function. Note it will be difficult to estimate the slope at the beginning and end. You donÕt have the luxury of points before and after. Discuss with your group members what is reasonable.
Mile |
Time on Clock |
Mile |
Time on Clock |
1 |
7:36 |
7 |
55:07 |
2 |
15:29 |
8 |
1:02:50 |
3 |
23:25 |
9 |
1:10:29 |
4 |
31:23 |
10 |
1:18:20 |
5 |
39:20 |
11 |
1:26:08 |
6 |
47:18 |
13.1 |
1:42:58 |
Activity 2:
Estimating the derivative using a graph, and translating back.
Each of you will sketch an arbitrary function on a piece of paper, labeling it ÒOriginal CurveÓ and putting your name on it. You will then pass your graph to someone else; they will graph the derivative function on a separate sheet of paper, labeled with ÒDerivative Curve for <insert name here>Ó. The person drawing the derivative will have to carefully estimate the slopes, so a scale is needed. I will show you in class the method I use to estimate these slopes. It involves placing a straight edge tangent to the curve, and finding the rise over run for that angle. This is repeated for a number of x-values.
After sketching the derivative, the second person will pass the derivative graph to a third person (keep the original aside to compare with later); the third person will attempt to redraw the original graph based solely on the information from the derivative graph. Caution: this last part is tricky, as the starting location is not unique. You need to arbitrarily pick a y-intercept to get started. From there, the derivative graph shows you how steep the graph needs to be at that point, so draw a little line segment with that slope. Move over slightly, and repeat the process.
I will show you an example in class before you attempt this activity. If everyone has done the estimates correctly, the graph the third person draws should match the ÒOriginal CurveÓ graph. If there are discrepancies, the two sketchers should resolve them. It might be that the person drawing the derivative made poor estimates, or it may be that the third person didnÕt translate the information well.
Activity 3:
Estimating using local linearity.
Work on problem 2, parts d and e, on page 133. These parts are about predicting new values using local linearity (or in this case extrapolating as 7 feet is beyond the available data).
nDeriv( (MATH 8) will produce an estimate for the derivative at a point. The syntax is nDeriv( expression, variable, value). expression is the formula for the function. I will often use Y#, having already stored the function in a Y variable. variable is generally x, but you have some flexibility here in case you want another letter to be the variable. value is whatever number youÕre interested in. When using nDeriv( to graph the entire derivative function in the graphing window, use x here instead. Example: nDeriv( Y1, x, x).
Goals: Realize that the derivative can be viewed
as a function.
Skills:
¥
Evaluate derivatives from tabular data. When
information is available in tabular form, we cannot Òzoom inÓ to get a limit of
secant slopes. We have only a few
choices to estimate the derivative at each x-value. Generally, the best option is to
average the secant slope before the point with the secant slope after the
point. This is algebraically
equivalent to finding the secant slope for the two points before and after.
¥
Interpret the derivative verbally. For
problems with a real-world setting, you should be able to use the value of the
derivative at a point in an English sentence. For example, you may say, ÒAt a production level of 1,000
car seats, we can expect profits to rise $10 for every additional car seat
produced.Ó If you are having
trouble with this verbal description of the derivative, one thing that may help
is to pay close attention to the units involved, for instance dollars, or
number of car seats produced. The
examples in Section 2.3 should help you understand this verbal phrasing and
interpretations of the derivative.
¥ Understand local linearity and how to use it estimate new values. If we are close enough to a point where we know the tangent slope, we can project the tangent line a short way and use it to estimate the value of the function at that new point. Caution: if the line is very ÒcurvyÓ at this spot, our tangent line will poorly represent the function, so it is important to only use this method very close to the known derivative value.
¥
Know how to use the TI-83 to produce a graph of the
estimated derivative of a formula.
The command nDeriv( will
estimate the derivative numerically with a small secant line. If we use this in the Y= window, we can
graph the entire derivative function on the graphing window. The syntax for this is nDeriv( Y#, x, x).
Reading: Sections 2.4 and 2.5.
Activity: Introduction to the Second
Derivative. Economic Examples.
After discovering that the derivative is a function just like the original curve, there is no reason we cannot take the derivative of the derivative. This is called the second derivative, and often reflects useful information in real world problems. It is the change in the change of a function. The second derivative also can be thought of as the curvature of a function. You have probably seen this idea already in terms of concavity. In particular, if the second derivative is positive, we say we have positive concavity, and the other way around for negative values.
When we look at the information from the first and second derivatives, there are four main situations of interest. The first derivative can be either positive or negative (or zero, but we will address that situation later) and the second derivative can be either positive or negative.
1) Positive first derivative, positive second derivative: an increasing curve that is getting steeper.
2) Positive first, negative second: an increasing curve that is leveling off, approaching a peak.
3) Negative first, positive second: a decreasing curve that is leveling off, approaching a minimum.
4) Negative first, negative second: a decreasing curve that is falling faster.
The Leibniz notation gets a little messy for second derivatives. The best way to phrase them is to use the prime notation, adding another prime for the second derivative. We usually say Òf double primeÓ, referring to . Note the messy Leibniz notation on page 119.
One important application of the derivative is the idea of marginal analysis. In fact, the term marginal is synonymous with derivative. If either the cost function or the revenue function is a straight line, then the marginal cost or revenue is simply the slope of that line. We will look at this topic again in Section 4.4 (Day 15), after we explore the shortcut formulas to differentiation.
In Activity 3 we revisit the concepts of marginal cost and marginal revenue. The important notion is that we are talking about the cost or revenue of the next item only. Because quantity is our independent variable, this marginal cost is the same as the derivative of cost, expressed in units of dollars per item. Usually, quantity can only be expressed as integers, so to calculate marginal cost or revenue directly, we subtract two sequential values, for example the difference between the cost to make 10 items and 11 items represents the marginal cost of the 10th item (or the 11th item). We can also approximate marginal cost using the derivative.
Activity 1:
Comparing a function to its first and second derivatives.
Enter , along with its first and second derivatives, in the Y= window. (See calculator commands below.) Select only the second derivative and use the window -2 < x
< 2 and -2 < y < 2. Make statements about the original
function given what you see about the second derivative. Repeat using just the
first derivative. Before graphing
the original function, make a sketch that satisfies your statements. Then compare and see how close you
were. If you are off in any of
your statements, closely examine where you went wrong.
Activity 2:
Interpreting derivatives in a real world setting.
Problem 30 page 132. Parts c and d are especially important; you must be able to convert the mathematical info into real world uses. In this case, the context of declining graduation rates is very important to school officials.
Activity 3: Marginal
cost and revenue.
Problem 10 page 129. Estimate values for the marginal cost and revenue at both 50 and 90. Use these figures in your answers.
There isnÕt a separate command on the TI-83 for the second derivative; it is simply the derivative of the first derivative. The easiest way to get the calculator to estimate the second derivative function is to use these two Y= functions. Put your formula in Y1. In Y2, put nDeriv( Y1, x, x). In Y3, put nDeriv( Y2, x, x).
Goals: Investigate
the properties of the second derivative.
Skills:
¥
Be able to graph the second derivative on the TI-83. Using
nDeriv(
will produce a numerical derivative of a formula. If we repeat the command on the new formula, we will
approximate the second derivative.
I recommend keeping these two commands in Y2 and Y3 for the rest of the semester. Put the formula you want to analyze in Y1. Use Y4 to Y0 for any other functions you want to graph.
¥
Understand what the second derivative says about the
concavity of a function. The second derivative measures the concavity of a
function. When it is positive, we
know the original function is bowl-shaped (concave up); when it is negative,
the original function is humped (concave down). When the second derivative is zero, it is neither
bowl-shaped nor humped; rather it is very nearly linear at that point. Earlier we talked about local
linearity; when the second derivative is zero, we might think of that point of
the curve being even more
locally linear!
¥
Be able to convert second derivative facts into everyday
English. Because the second derivative is a change in the
first derivative, when we convert to an English description, we have to talk
about the rate of change in the rate of change. For example, the speed of the car is increasing. Sometimes we have special words for
these derivatives. With the motion
of an object, the first derivative is speed and the second derivative is
acceleration.
¥
Realize that marginal costs/revenues/etc are simply
derivatives. Marginal costs, revenues, profit, etc are important
ideas in economics. Because the
marginal cost is the cost of the next item, we are just talking about the slope of the tangent line, which
is the derivative. Similarly for
revenue, the derivative is the marginal revenue. We will explore these ideas more in Section 4.4.
Reading: Sections 3.1 and 3.2.
Activity: Using Polynomial and Exponential derivative formulas. Quiz 3 today.
A calculator approximation for the derivative function is convenient, but there will be times when we would rather have an exact formula. Fortunately, there are theorems (shortcuts) we can use. We wonÕt prove many of these results, but we will use them to produce formulas. Chapter 3, therefore, is only concerned with the algebraic point of view. When we have tabular data, graphs, or verbal descriptions, we cannot use these theorems.
Several of the theorems apply to any function. Others are specific to particular forms. The general rules are the additive constant rule, the multiplicative constant rule, the addition/subtraction rule, the product rule, the quotient rule, and the chain rule. The specific functions are the power rule, the exponential rule, and the logarithmic rule.
Additive constant rule: For this rule, we can make a quick argument to see the answer. What happens to the slope of a curve when we add a constant to it? Adding the same constant to every value simply lifts or lowers the entire curve that much, but doesnÕt change the shape at all. Thus, the additive constant rule is that there is no change to the derivative. .
Multiplicative constant rule: It is a little harder to verbally prove this rule, but we can see for straight lines that multiplying by a constant increases the slope by that constant. With algebra, and the definition of derivative on page 135, we can discover that the derivative of a multiplied function is multiplied by the same amount. .
Addition/subtraction rule: Again, using algebra is the easiest way to prove this rule, but we will accept the result on faith. (If you would like to see the algebra, see me after class.) Basically, the derivative of a sum is the sum of the derivatives. .
Power rule: To prove the power rule, we need the binomial theorem, and lots of algebra. Again, we will accept this result on faith. . When we combine this rule with the multiplicative constant rule, we get the most common rule weÕll use: . We need to use this rule for reciprocals and radicals, as they can be written as exponents. This means you will have to recognize that square roots, and reciprocals, are power functions. We will do some examples in class.
Exponential rule: The
exponential class of functions is quite unique. They are
their own derivatives. Activity 2
below will hopefully convince you of this. The text gives a simpler version of this rule, but I like to
start with the more complicated version, which is actually a result of the
chain rule (Day 12). . When f(x) is a linear function, is the slope, so
that constant is multiplied in front.
Example: . When the base
is e, ln(e) = 1, so it is even simpler. .
Logarithmic rule: The logarithmic rule is very simple: . I will show a simple proof of this in class based on the exponential rule.
Activity 1: Try some
basic expressions.
For each of the
following functions, plot the function in Y1, its nDeriv( in Y2, and your candidate answer in Y4. Using trace, check to see if your
answer is right. (Compare Y2 to Y4.) (Note in problem 5 you will have to
make up values for k and a. This
sort of problem is why knowing algebra is still important.)
1)
2)
3)
4)
5)
6)
Activity 2:
Discovering the unique character of the exponential functions.
Graph and its derivative in the same window. What is the doubling time for ? What is the doubling time for its derivative? These two doubling times imply an important result. Use this result to deduce the formula for the derivative of .
Goals: Learn
and use the basic rules for differentiation shortcuts.
Skills:
¥
Know the Rule for Sums.
.
¥
Know the Rule for Powers.
. Note that n
can be any number, including fractions and negatives.
¥
Know the Rules for Exponential Functions. . This rule actually
uses the chain rule, coming up tomorrow, but I like to use the more general
rule now.
¥
Know the Rule for the Natural Logarithmic Function. .
¥
Realize that your nDeriv( function will verify that you have a
correct derivative. By graphing the numerical derivative on your
calculator (nDeriv),
along with what you think the answer is, you can verify if your answer is
correct. You can either compare
the values for a few haphazardly chosen values, or you can graph their
difference on a separate window.
If they are the same, the difference should be zero (or very close but
not exact due to rounding).
Reading: Sections 3.3 and 3.4.
Activity: Practicing the Chain, Product, and Quotient Rules. Homework 3 due today.
Today we practice formulas. I will show you how the product, quotient, and chain rules work. Then we will spend time practicing.
The chain rule is used in composed functions. The idea is that you first must calculate one functionÕs result before you can finish the calculation. This first function, often called the ÒinnerÓ function, can be substituted with another letter. But the key is that the ÒouterÓ function (what we do to the inner functionÕs result) must be evaluated at the inner functionÕs result. If we use the symbol x for the input to the inner function, then we canÕt use x as the input to the outer function. We still do the derivative rules the same, we just evaluate the outer function at the inside functionÕs result, not at x. Hopefully, our class discussion will make this clearer.
A note that seems to help people understand how to use the chain rule: ultimately, the chain rule is a product of the derivatives of the inner and outer functions. To use the rule effectively, you must be able to decompose the function into its parts. This is why understanding composed functions from Chapter 1 is so critical to success in this section of the material.
Activity 1:
Practicing the Product, Quotient, and Chain Rules.
Calculate the derivatives of the following functions. Be sure to first decide whether the function requires the product rule, the chain rule, the addition rule, etc. Then check your answers on your calculator using nDeriv.
1) . (Use the
product rule.)
2) . (Expand first, then use the power rules.)
3) .
4) .
5) . (Expand first, then use the power rule.)
6) . (Use the chain rule.)
7) .
8) . (This should require two substitutions, or two uses of the chain rule.)
Goals: Become familiar with the product,
quotient, and chain rules.
Skills:
¥
Identify the particular derivative rule needed for a
problem. For many functions, only one of the derivative rules
we have learned is actually used.
(Of course, for some functions, more than one type of rule might be
present.) Your task, then, is to
be able to identify which particular rule or rules are needed. This skill will come with
practice. It is up to you to put
in the time so that you have the experience to choose the proper rules. There are a lot of problems on page 173
for you to practice on.
¥ Know the Rule for Products. . It is important to note that the product rule is definitely not the product of the derivatives. That is actually closer to what the chain rule says.
¥
Know the Rule for Quotients. . To remember
this rule, IÕve memorized the little ditty ÒLow dee high, less high dee low,
square the bottom down belowÓ.
IÕve never forgotten the quotient rule because of it!
¥ Know the Rule for Compositions (Chain Rule). . You must understand composed functions to use this rule correctly. If you cannot identify what g(x) is, you canÕt get the correct derivative in front. You also need to be able to ÒreplaceÓ g(x) with x in the f function to get the proper derivative there, then again ÒreplaceÓ x with g(x).
¥
Identify the particular derivative rule needed for a
problem. For many functions, only one of the derivative rules
we have learned is actually used.
(Of course, for some functions, more than one type of rule might be
present.) Your task, then, is to
be able to identify which particular rule or rules are needed. This skill will come with
practice. It is up to you to put
in the time so that you have the experience to choose the proper rules. There are a lot of problems on page 173
for you to practice on.
¥
Reading: Section 4.1.
Activity: Exploring Local Extrema. Quiz 4 today.
Now that we have learned some formulas, we can make use of this information algebraically to find interesting places on curves. In particular, we can find peaks and valleys, or more formally, local maxima and minima (together called extrema). You may think at first with our powerful calculator that we donÕt need algebra any more. While our machines help us in many circumstances, there is still a use for analytical results. For example, the calculator will help us find the turns in a polynomial, but only if we have a suitable window already. Algebraic results help us find the proper window. We will explore this in Activity 1.
Another circumstance where algebra is necessary is when the parameters of a model are unspecified. Activity 2 today addresses this situation.
Activity 1:
Analyzing polynomial turns.
Without doing calculus, try to find the part of this cubic where the critical points are. . Now, find the critical points algebraically. Use the first derivative test to classify the critical points. Use the second derivative test to classify the critical points.
Activity 2: Finding
the conditions on a cubic so it has two turns.
The general form for a cubic polynomial is . However, we know that some cubics have no extrema, such as . What conditions on the parameters cause a cubic to have none, one, or two critical points? Hint: you will need to use the quadratic formula and note where the discriminant is negative, zero, or positive.
Activity 3: Critical
points of a non-polynomial.
Without doing calculus, try to find the part of this function where the critical points are. . Now, find the critical points algebraically. Use the first derivative test to classify the critical points. Use the second derivative test to classify the critical points.
Activity 4: Using a
table of derivative values to find the maximum and minimum.
Problem 20 page 181.
Goals: Understand
critical points, and how to classify them.
Skills:
¥
Know the definition of a Critical Point. Locations
on the graph of a function where the derivative is either zero, or undefined,
are critical points. Places with zero slope might be maxima,
minima, or neither. Important
examples to keep in mind are the cubic power function, which has a critical
point that is neither a maximum nor a minimum, and the absolute value function,
which has a critical point with an undefined derivative.
¥
Be able to use the First and Second Derivative Tests for
classifying extrema. The second derivative test is useful for determining
whether a critical point is a maximum or a minimum. Simply evaluate the second derivative at the candidate
point, and classify it as a maximum, a minimum, as it is negative or positive. If the second derivative is zero, we
must resort to the first derivative test.
To perform this test, we assess whether the first derivative is positive
or negative around the critical point.
If it is negative to the left and positive to the right, we have a
minimum. If it is positive to the
left and negative to the right, we have a maximum. If it is positive on both sides of a critical point or if it
is negative on both sides of the critical point, then we have a Òsaddle pointÓ,
which is neither a maximum nor a minimum.
Reading: Sections 4.2 and 4.3.
Activity: Exploring Inflection Points
and identifying Global Extrema. Homework 4 due today.
We have seen that the critical points of a function describe that functions extrema, if any exist. The critical points of the derivative function represent places where the concavity of the original function changes sign. These points are called inflection points. We discover them in just the same way we found critical points, but working with the second derivative instead of the first derivative. Remember that it is possible for the second derivative to be zero and yet the concavity doesnÕt change. The fourth degree power function is one example.
In addition to determining inflection points and critical points, we also want to determine global extrema. We have already talked about relative (or local) extrema. The overall maximum (or minimum) must be either one of the critical points, unbounded (such as with a vertical asymptote), or one of the endpoints (if the region is bounded). When you look for global extrema, I recommend making a list of the critical points, and endpoints. Then, after looking at the graph for places where the graph goes off to infinity in either direction, choose the largest for the maximum, and the smallest for the minimum. If the graph does go to infinity, the best phrase to use is ÒThere is no global maximum (or minimum).Ó
Asymptotes are straight lines that a graph approaches. y = 1/x
is an example with two asymptotes; there is a horizontal asymptote on the x-axis and a vertical asymptote on the y-axis.
We will mostly be concerned with only horizontal and vertical
asymptotes, but they could also be oblique (diagonal). Generally, when the denominator of a
rational function is zero, we have a possible vertical asymptote. While these are not critical points,
they are important to identify, as a function is unbounded at an
asymptote.
Activity 1:
Describing the interesting points in a function.
For each of the following functions, find all the interesting points/features, including critical points, extrema, inflection points, asymptotes, increasing and decreasing intervals, and positive and negative concavity.
1) [Hint: Use the TI-83.]
2) [Hint: The second derivative algebraically is tough; persevere, or use the TI-83.]
3) [Hint: The second derivative algebraically is tough; persevere, or use the TI-83.]
4)
5) , x ³ 0
Goals: Be
able to find and interpret points of inflection. Understand the difference between relative extrema and global extrema.
Skills:
¥
Know the definition of Inflection Points. Points
on a graph where the concavity changes sign are inflection points. We
normally detect these points by examining where the second derivative is
zero. However, we still must check
on each side of such candidates, as simply equaling zero is not the same as it
changing sign.
¥
Understand the overall strategy for analyzing and sketching
functions. Our overall strategy is to find the critical points,
the asymptotes (both vertical and horizontal), inflection points, intercepts,
and any other easy-to-find points.
You should be able to make both quantitative and qualitative
descriptions of functions/graphs/equations.
¥
Sketch graphs for equations with unspecified parameters. Using
the skills acquired in classifying critical points, and using the skills for
finding asymptotes, you should be able to sketch curves with unspecified
parameters. You may need to be
told whether the values of the coefficients are positive or negative, or over
what range the coefficients can have values. For example, for parabolas we know the vertex has an x-coordinate
of , where . It may be
difficult or impossible to graph the family of curves in general, as different
coefficients may yield differently shaped curves, but in most cases you can
construct an effective sketch.
¥
Be able to find global extrema. To find the overall
extrema (global extrema), we
examine all the critical points, as well as any endpoints of the domain or any
points with undefined derivative.
Caution: only looking at the critical points will not be sufficient, as
many functions have no global maximum or minimum due to the functionÕs values
approaching infinity.
Reading: Sections 4.4 and 4.5.
Activity: Economic Examples. Quiz 5 today.
Today we return to economic applications. Recall that profit is the difference between revenue and cost. The first thing to notice is that the quantity that maximizes revenue is not always the same quantity that maximizes the profit. We have several approaches to solving the maximum profit problem. We can simply calculate profit at all quantities and then choose the maximum. This can be tedious and time consuming. It might be much easier to use the calculus rules we have learned. Specifically, we know that when a derivative is zero, the function has a relative maximum or minimum. Because profit is a difference (), we can use the formulas from Chapter 3 to show that . Now, if we set the derivative to zero and solve, we find . We use this strategy now to solve problems with only a graph, or a table of marginal values: find where marginal cost and marginal revenue are equal. We will practice with all three approaches (tabular, graphical, algebraic) in Activity 1.
Another example using derivatives in economics is average cost. By dividing the cost function by quantity, we have the formula for average cost. Using the quotient rule (which I will do in class), we discover that the minimum cost occurs where average cost equals marginal cost. If we have the formulas, this will just be an algebra problem. If we have graphs, it will be easier, as there is a handy geometric solution (see page 204 figure 4.60).
Activity 1: Profit
maximization.
We will maximize profit using three sets of information: tabular, graphical, and algebraic.
Tabular: problem 8 page 200.
Graphical: problem 13 page 200.
Algebraic: problem 16 page 201.
Activity 2:
Exploring Average Cost.